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The minimum cross-sectional area of a human femur bone is [tex]5.5 \times 10^{-4} \, \text{m}^2[/tex]. The maximum compressional load at which fracture occurs is \(F\).

Hint: Ultimate compression strength for bones \(\sigma_c = 17 \times 10^7 \, \text{N/m}^2\). Ultimate tension strength for bones \(\sigma_t = 12 \times 10^7 \, \text{N/m}^2\).

a) 59500 N
b) 76500 N
c) 60000 N
d) 66000 N
e) 93500 N

Answer :

Final answer:

The maximum compression load at which fracture occurs can be calculated using the ultimate compression strength and the minimum cross-sectional area of the bone. Plugging in the given values, the maximum load is determined to be 93500 N.

Explanation:

The maximum compressional load at which fracture occurs in a human femur bone can be determined using the ultimate compression strength and the minimum cross-sectional area of the bone. The formula to calculate the maximum load is:



Maximum Load = Ultimate compression strength * Cross-sectional area



Plugging in the given values:



  1. Ultimate compression strength (σo): 17 x 107 N/m²
  2. Cross-sectional area (A): 5.5 x 10-4 m²



Putting the values into the formula:



Maximum Load = (17 x 107 N/m²) * (5.5 x 10-4 m²)



Simplifying the expression gives us:



Maximum Load = 93500 N



Therefore, the maximum compressional load at which fracture occurs is 93500 N.

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