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Answer :
The point where the electric field is equal to zero is located 1.00 meter from the positive charge and 1.00 meter from the negative charge.
To find the point between the 40 nc charge and 10 nc charge where the electric field is equal to zero, we need to use the formula for electric field:
E = kq/r^2
where E is the electric field, k is the Coulomb constant (9 x 10^9 Nm^2/C^2), q is the charge, and r is the distance between the charges.
Let's assume that the 40 nc charge is positive and the 10 nc charge is negative. Then, we can calculate the electric field at any point between the charges using the formula above.
At a point x meters from the positive charge and (2-x) meters from the negative charge, the electric field is given by:
E = kq1/(x)^2 + kq2/(2-x)^2
where q1 = 40 nc and q2 = -10 nc.
To find the point where the electric field is zero, we need to solve for x:
kq1/(x)^2 + kq2/(2-x)^2 = 0
40 x 10^-9/(x)^2 - 10 x 10^-9/(2-x)^2 = 0
Solving this equation gives us:
x = 1.00 m
Therefore, the point where the electric field is equal to zero is located 1.00 meter from the positive charge and 1.00 meter from the negative charge.
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