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3. A radioactive compound with a mass of 360 grams decays at a rate of [tex]3\%[/tex] per hour. Which equation represents how many grams of the compound will remain after 5 hours?

A. [tex]C=360(0.03)^5[/tex]

B. [tex]C=360(1-0.03)[/tex]

C. [tex]C=360(0.97)^5[/tex]

D. [tex]C=360(1+0.03)^5[/tex]

Answer :

To find out how much of the radioactive compound will remain after 5 hours, we need to use the formula for exponential decay, which is:

[tex]\[ C = P \times (1 - r)^t \][/tex]

Where:
- [tex]\( C \)[/tex] is the remaining amount.
- [tex]\( P \)[/tex] is the initial amount, which is 360 grams.
- [tex]\( r \)[/tex] is the decay rate, which is 3% or 0.03.
- [tex]\( t \)[/tex] is the time in hours, which is 5 in this case.

Let's go through the steps:

1. Substitute the initial mass ([tex]\( P \)[/tex]), the decay rate ([tex]\( r \)[/tex]), and the time ([tex]\( t \)[/tex]) into the formula:
[tex]\[
C = 360 \times (1 - 0.03)^5
\][/tex]

2. Perform the subtraction within the parentheses:
[tex]\[
1 - 0.03 = 0.97
\][/tex]

3. Raise the result to the power of the time, which is 5:
[tex]\[
0.97^5 \approx 0.858734025
\][/tex]

4. Multiply the initial mass by the result of the previous calculation:
[tex]\[
C = 360 \times 0.858734025 \approx 309.144
\][/tex]

So, approximately 309.144 grams of the compound will remain after 5 hours.

Thus, the correct equation that represents how many grams of the compound will remain after 5 hours is:
[tex]\[ C = 360 \times (0.97)^5 \][/tex]

The correct answer is C. [tex]\( C=360(0.97)^5 \)[/tex].

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