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Answer :
Final answer:
The speed of the tennis ball when it reaches the sidewalk below will be 34.3 m/s, matching option D.
Explanation:
This is a high school physics problem dealing with the concepts of free fall and kinematics. When the student on the balcony launches the ball straight up at a velocity of 29.4 m/s, the ball will eventually reach peak height then fall back down due to gravity. Presuming the absence of air resistance, we apply the equation for final velocity v_f = sqrt(v_i^2 + 2*a*d), where v_i is the initial velocity, a is acceleration (equal to gravity when the object is in free fall), and d is the distance. Plugging in the given values (v_i = 29.4 m/s, a = -9.81 m/s², d = -10 m), the final speed whereby negative indicates direction not magnitude would be 34.3 m/s taking the absolute would yield 34.3m/s, matching option D.
Learn more about Free Fall Kinematics here:
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