We appreciate your visit to Solve the following numerical problems a If a car is moving with the speed of 36 km hr convert it into m s b If. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Here are the solutions to each of the given problems:
a. Convert 36 km/hr to m/s:
1 kilometer equals 1000 meters, and 1 hour equals 3600 seconds.
Using the conversion formula from kilometers per hour to meters per second:
[tex]\frac{36 \text{ km/hr} \times 1000}{3600} = 10 \text{ m/s}[/tex]
So, the speed of the car in meters per second is 10 m/s.
b. Calculate the speed of the car traveling 900 m in 30 seconds:
Speed is calculated using the formula:
[tex]\text{Speed} = \frac{\text{Distance}}{\text{Time}}[/tex]
Here, the distance is 900 meters, and the time is 30 seconds.
[tex]\text{Speed} = \frac{900 \text{ m}}{30 \text{ s}} = 30 \text{ m/s}[/tex]
Therefore, the speed of the car is 30 m/s.
c. Determine the acceleration of the taxi:
Acceleration is the change in velocity divided by the time taken for the change.
Initial velocity [tex]u = 5 \text{ m/s}[/tex]
Final velocity [tex]v = 20 \text{ m/s}[/tex]
Time [tex]t = 15 \text{ s}[/tex]
[tex]\text{Acceleration} = \frac{v - u}{t} = \frac{20\text{ m/s} - 5\text{ m/s}}{15\text{ s}} = \frac{15\text{ m/s}}{15\text{ s}} = 1\text{ m/s}^2[/tex]
So, the acceleration of the taxi is 1 m/s².
**d. Calculate the distance covered by the bus: **
Using the formula for distance:
[tex]\text{Distance} = \text{Speed} \times \text{Time}[/tex]
Given speed [tex]= 10 \text{ m/s}[/tex] and time [tex]= 20 \text{ s}[/tex],
[tex]\text{Distance} = 10\text{ m/s} \times 20\text{ s} = 200\text{ m}[/tex]
Thus, the bus covers 200 meters in 20 seconds.
e. Work done by the man throwing the stone:
Since the stone falls down 500 meters from him, assuming he throws the stone horizontally (simplifying it to a theoretical physics problem where vertical work/dynamics like gravity aid are ignored for initial work computation), work done is given by:
[tex]\text{Work} = \text{Force} \times \text{Distance}[/tex]
But there's no movement in the direction of the applied force here to count as physics work in this setting. The problem seems formulated without comprehensive real-world work detailed calculations.
f. Power of the worker moving mass:
Given:
- Mass [tex]= 60 \text{ kg}[/tex]
- Distance [tex]= 300 \text{ m}[/tex]
- Time [tex]= 1 \text{ minute} = 60 \text{ seconds}[/tex]
First, calculate the work done:
[tex]\text{Work} = \text{Weight} \times \text{Distance} = (60\text{ kg} \times 9.8\text{ m/s}^2) \times 300\text{ m} = 60 \times 9.8 \times 300[/tex]
[tex]\text{Work} = 176400 \text{ J} (Joules)[/tex]
Now, calculate the power:
[tex]\text{Power} = \frac{\text{Work}}{\text{Time}} = \frac{176400 \text{ J}}{60\text{ s}} = 2940 \text{ W} \text{ (Watts)}[/tex]
Thus, the power exerted by the worker is 2940 Watts.
Thanks for taking the time to read Solve the following numerical problems a If a car is moving with the speed of 36 km hr convert it into m s b If. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
