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What is the mass percent of [tex]CaCl_2[/tex] in a solution made by dissolving 35.5 g of [tex]CaCl_2[/tex] in 345 g of [tex]H_2O[/tex]?

A. 10.3%
B. 9.3%
C. 11.4%
D. 8.7%

Answer :

Final answer:

The mass percent of CaCl2 in the solution made by dissolving 35.5 g of CaCl2 in 345 g of H2O is 9.3% after calculating and rounding to the correct significant figures.

Explanation:

The mass percent of CaCl2 in the solution can be calculated using the formula mass percent = (mass of the solute / (mass of the solute + mass of the solvent)) x 100%. In this case, we substitute 35.5 g for the mass of CaCl2 and 345 g for the mass of water (H2O).

Mass percent = (35.5 g / (35.5 g + 345 g)) x 100% = (35.5 g / 380.5 g) x 100% = 9.3351%. After rounding to the correct significant figures, we get 9.3%.

Therefore, the correct answer is b) 9.3%.

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