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Answer :
Final answer:
The specific gravity of 1.0 for a fluid translates to a density equal to water, which is approximately 1000 kg/m³. Multiplying by the acceleration due to gravity, the specific weight is calculated as 1000 kg/m³ × 9.81 m/s² = 9810 N/m³, thus the answer is 98.1 N/m³.
Explanation:
If a fluid has a specific gravity of 1.0, its density is equal to the density of water. The density of water is very nearly 1000 kg/m³ at 4°C, and while it changes slightly with temperature, it is often approximately taken as 1000 kg/m³ for calculations at room temperature. The specific weight of a substance is defined as its weight per unit volume, which is the product of its density (ρ) and the acceleration due to gravity (g).
Since the acceleration due to gravity is approximately 9.81 m/s² on Earth, the specific weight (γ) of the fluid, if it's water at 26°C with a specific gravity of 1.0, can be calculated as follows:
ρ × g = (1000 kg/m³) × (9.81 m/s²) = 9810 N/m³.
Therefore, the correct answer is C) 98.1 N/m³.
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