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How many grams of ethanol, C\(_2\)H\(_5\)OH, can be boiled with 452.6 kJ of heat energy? The molar heat of vaporization of ethanol is 38.6 kJ/mol.

Answer :

452.6 kJ of heat energy can boil approximately 539.77 grams of ethanol.To determine the mass of ethanol that can be boiled with 452.6 kJ of heat energy, we need to use the molar heat of vaporization of ethanol.

The molar heat of vaporization of ethanol is given as 38.6 kJ/mol. This means that it takes 38.6 kJ of heat energy to vaporize one mole of ethanol.
To find the mass of ethanol, we need to convert the given heat energy to moles and then to grams.
Step 1: Convert the given heat energy to moles.
To do this, we divide the given heat energy by the molar heat of vaporization:
452.6 kJ / 38.6 kJ/mol = 11.71 mol

Step 2: Convert moles to grams.
To convert moles to grams, we multiply the number of moles by the molar mass of ethanol. The molar mass of ethanol (C2H5OH) is calculated by adding the atomic masses of carbon (C), hydrogen (H), and oxygen (O):
C: 12.01 g/mol
H: 1.01 g/mol (there are 5 hydrogen atoms in ethanol)
O: 16.00 g/mol
Molar mass of ethanol: 2(12.01 g/mol) + 6(1.01 g/mol) + 1(16.00 g/mol) = 46.07 g/mol

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