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The product of two integers is [tex]112[/tex]. One number is four more than three times the other. Which of the following equations could be used to find one of the numbers?

A. [tex]3x^2 + 4x = 112[/tex]
B. [tex]3x^2 + 4 = 112[/tex]
C. [tex]4x^2 + 3x = 112[/tex]
D. [tex]4x^2 + 3 = 112[/tex]

Answer :

To solve this problem, we need to set up an equation based on the conditions given:

1. Let [tex]\( x \)[/tex] be one of the integers.
2. Then, the other integer, according to the problem, would be [tex]\( 3x + 4 \)[/tex] because it is four more than three times the first integer.

The problem also states that the product of these two integers is 112. This can be expressed as:

[tex]\[ x \times (3x + 4) = 112 \][/tex]

Now, let's simplify and solve this equation:

- Distribute [tex]\( x \)[/tex] in the equation:
[tex]\[
x \cdot (3x + 4) = 3x^2 + 4x
\][/tex]

- Set the expression equal to 112:
[tex]\[
3x^2 + 4x = 112
\][/tex]

The equation [tex]\( 3x^2 + 4x = 112 \)[/tex] matches with option A. Therefore, the equation that could be used to find one of the numbers is:

A. [tex]\( 3x^2 + 4x = 112 \)[/tex]

This equation reflects the relationship described in the problem and can be solved to find the value of [tex]\( x \)[/tex].

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