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A 10.0-kg bucket is lowered vertically by a rope with 165 N of tension at a given instant.

What is the acceleration of the bucket?

Answer :

The acceleration of the bucket is 16.5 m/s² as determined by the equation a = F / m, where F is the tension in the rope (165 N) and m is the mass of the bucket (10.0 kg).

The tension in the rope can be considered as the net force acting on the bucket. According to Newton's second law of motion, the net force is equal to the mass of the object multiplied by its acceleration (F = m * a). In this case, the tension force is 165 N, and the mass of the bucket is 10.0 kg.

By rearranging the formula, we can solve for acceleration:

a = F / m

Substituting the given values, we have:

a = 165 N / 10.0 kg

a ≈ 16.5 m/s²

Therefore, the acceleration of the bucket is approximately 16.5 m/s².

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