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it took 2.570×103 j to raise the temperature of a sample of water from 12.9 °c to 38.3 °c. convert 2.570×103 j to calories.

Answer :

2.570×[tex]10^3[/tex] joules is equal to 614.43 calories.

To convert joules to calories, you can use the conversion factor that 1 calorie is equal to 4.184 joules.

Given that it took 2.570×[tex]10^3[/tex] J to raise the temperature of the water, we can convert it to calories using the conversion factor:

2.570×[tex]10^3[/tex] J * (1 calorie / 4.184 J) = 614.43 calories

To know more about calories refer here

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