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Answer :
Final answer:
The percentage of the (S) form in the mixture is 60.0%.
Explanation:
The specific rotation of a pure (S) enantiomer is +61.0 degrees. To find the percentage of the (S) form in a mixture, we can use the formula: Percentage of (S) form = (Specific Rotation of the Mixture - Specific Rotation of the (R) form) / (Specific Rotation of the (S) form - Specific Rotation of the (R) form) x 100
To find the percentage of the (S) enantiomer in the mixture, you can use the formula: % (S) enantiomer = (Observed rotation / Specific rotation of (S)) * 100.
% (S) enantiomer = (+36.6 / +61.0) * 100 = 60%.
So, the (S) enantiomer makes up 60% of the mixture, while the (R) enantiomer constitutes the remaining 40%.
Plugging in the values given, we get: Percentage of (S) form = (+36.6 - 0) / (+61.0 - 0) x 100 = 60.0%
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