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Answer :
Final answer:
A tank with the dimensions of 3 feet by 5 feet by 6 inches can hold a total of 56.25 gallons of fuel, with the volume being calculated in cubic feet and then converted to gallons using the conversion factor of 7.5 gallons per cubic foot.
Explanation:
To determine how much fuel can be put into a tank with dimensions of 3 feet by 5 feet by 6 inches, we must first calculate the volume of the tank in cubic feet and then convert it to gallons using the provided conversion factor.
Step 1: Calculate the Volume in Cubic Feet
The volume of a rectangular prism (tank) is given by the formula volume = length × width × height. However, care must be taken to ensure all dimensions are in the same units, so we must convert 6 inches into feet. Since 1 foot is 12 inches, 6 inches is equal to 0.5 feet.
Using the dimensions given:
volume = 3 ft × 5 ft × 0.5 ft = 7.5 cubic feet.
Step 2: Convert Volume in Cubic Feet to Gallons
Using the conversion factor, 1 cubic foot holds 7.5 gallons of fuel, the total volume in gallons is:
7.5 cubic feet × 7.5 gallons/cubic foot = 56.25 gallons.
Therefore, a tank measuring 3 feet by 5 feet by 6 inches can hold a total of 56.25 gallons of fuel.
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Final answer:
The tank can hold 56.25 gallons of fuel.
Explanation:
To find the volume of the tank, we need to multiply its length, width, and height together. Given that the tank measures 3 feet by 5 feet by 6 inches, we need to convert the measurements to the same unit. Since 1 foot equals 12 inches, the tank measures 36 inches by 60 inches by 6 inches. Multiplying these dimensions, we get a volume of 12,960 cubic inches.
Next, we need to convert the volume to gallons. Since 1 cubic foot equals 1,728 cubic inches, we can divide the volume by 1,728 to get the volume in cubic feet. Dividing 12,960 by 1,728 gives us a volume of 7.5 cubic feet. Finally, we can multiply the volume in cubic feet by the conversion factor of 7.5 gallons per cubic foot to find that the tank can hold 56.25 gallons of fuel.
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