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You are driving a car behind another car. Both cars are moving at a speed of 80 km/h. The reaction time of the driver in Car 2 is 0.60 seconds. Assume Car 2's brakes are slightly more effective than Car 1's brakes.

What is the minimum distance behind the car in front that you should maintain to avoid crashing into its rear if the driver of that car slams on the brakes?

Answer :

Answer:

minimum distance will be 13.33 m

Explanation:

We have given the speed of both the car = 80 km/h

We know that 1 km =1000 m

And 1 hour = 60×60 =3600 sec

So [tex]80km/h=\frac{80\times 1000}{3600}=22.22m/sec[/tex]

Reaction time is given as t = 0.60 sec

Minimum distance will be equal to the distance driver needed during reaction time

So minimum distance = u ×t =22.22 ×0.60=13.33 m

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Rewritten by : Barada

The minimum distance behind the car in front to drive so that the crash into the car's rear end if the driver of car 1 slams on the brakes should be 13.33 m.

What is speed of a object?

Speed or velocity of a object is the ratio of distance traveled by the object with the time taken.

Given information-

The speed of car 1 and car 2 is 80 km/h.

The reaction time of the car 2 driver is 0.60 seconds.

Convert the unit of speed into the m/s by multiplying it with 5/18 as,

[tex]v=\dfrac{80\times5}{18} \\v=22.22 \rm m/s[/tex]

Thus the speed of the car is 22.22 m/s.

Now the reaction time is 0.60 seconds. Thus the minimum distance can be given as,

[tex]d=22.22\times0.6\\d=13.33 m[/tex]

Hence the minimum distance behind the car in front to drive so that the crash into the car's rear end if the driver of car 1 slams on the brakes should be 13.33 m.

Learn more about the velocity here;

https://brainly.com/question/6504879