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Answer :
To solve the division problem [tex]\(208 \div 16\)[/tex] using long division, follow these steps:
1. Set up the problem: Write 208 under the division symbol and 16 outside, to the left.
2. Divide the first part of the number:
- Look at the first two digits of 208, which are 20.
- Determine how many times 16 can go into 20. Since 16 goes into 20 one time, write 1 above the division bar.
3. Multiply and subtract:
- Multiply 1 (the number above) by 16, which equals 16.
- Subtract 16 from 20 to get a remainder of 4.
4. Bring down the next digit:
- Bring down the next digit (8) from 208, to the right of 4, making it 48.
5. Divide again:
- Determine how many times 16 can go into 48. 16 goes into 48 three times.
- Write 3 above the division bar next to the 1.
6. Multiply and subtract again:
- Multiply 3 by 16, which equals 48.
- Subtract 48 from 48 to get a remainder of 0.
Now, you have no more digits to bring down, and the remainder is 0, indicating the division is complete.
Thus, [tex]\(208 \div 16 = 13\)[/tex] with no remainder.
1. Set up the problem: Write 208 under the division symbol and 16 outside, to the left.
2. Divide the first part of the number:
- Look at the first two digits of 208, which are 20.
- Determine how many times 16 can go into 20. Since 16 goes into 20 one time, write 1 above the division bar.
3. Multiply and subtract:
- Multiply 1 (the number above) by 16, which equals 16.
- Subtract 16 from 20 to get a remainder of 4.
4. Bring down the next digit:
- Bring down the next digit (8) from 208, to the right of 4, making it 48.
5. Divide again:
- Determine how many times 16 can go into 48. 16 goes into 48 three times.
- Write 3 above the division bar next to the 1.
6. Multiply and subtract again:
- Multiply 3 by 16, which equals 48.
- Subtract 48 from 48 to get a remainder of 0.
Now, you have no more digits to bring down, and the remainder is 0, indicating the division is complete.
Thus, [tex]\(208 \div 16 = 13\)[/tex] with no remainder.
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