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Answer :
Final answer:
In a perfectly inelastic collision, the resulting velocity after the tackle can be calculated using the principle of conservation of momentum. Therefore, the resulting velocity after the tackle is approximately 2.639 m/s in some combination of east and north directions which is none of the above options.
Explanation:
For a perfectly inelastic collision, the total momentum before the collision is equal to the total momentum after the collision.
Before the collision, the rugby player's momentum is 185 kg * 4.00 m/s = 740 kg·m/s east, and the opponent's momentum is 97.5 kg * 4.35 m/s = 423.375 kg·m/s north.
After the collision, the masses stick together, so the total mass is 185 kg + 97.5 kg = 282.5 kg. The resulting velocity can be found using the principle of conservation of momentum:
(740 kg·m/s east) + (423.375 kg·m/s north) = (282.5 kg * v)
Solving for v gives:
v = (740 kg·m/s east + 423.375 kg·m/s north) / 282.5 kg ≈ 2.639 m/s
Therefore, the resulting velocity after the tackle is approximately 2.639 m/s in some combination of east and north directions.
Learn more about inelastic collision here:
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