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A 25.0 mL volume of HCl solution of unknown concentration is titrated with a 0.148 M NaOH solution. Neutralization of the HCl solution requires 39.1 mL of the NaOH solution. Calculate the concentration of the HCl solution.

Answer :

The concentration of the HCl solution is 0.231 M.

To calculate the concentration of the HCl solution, we can use the concept of stoichiometry.

The balanced chemical equation for the reaction between HCl and NaOH is:

HCl + NaOH → NaCl + H2O

From the equation, we can see that 1 mole of HCl reacts with 1 mole of NaOH.

First, let's calculate the number of moles of NaOH used in the titration:

moles of NaOH = concentration of NaOH solution * volume of NaOH solution used

= 0.148 M * 39.1 mL

= 0.0057818 mol

Since the stoichiometry of the reaction is 1:1, the number of moles of HCl in the solution is also 0.0057818 mol.

Next, we can calculate the concentration of the HCl solution:

concentration of HCl solution = moles of HCl / volume of HCl solution

= 0.0057818 mol / 25.0 mL

= 0.231 M

Therefore, the concentration of the HCl solution is 0.231 M.

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