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Answer :
Final answer:
The sodium content of 1g of ampicillin sodium is 2.70 mEq, calculated by first converting the mass of ampicillin sodium to moles and then converting moles to milliequivalents.
Explanation:
To calculate the sodium content in mEq of 1g of ampicillin sodium with a molecular weight (MWt) of 371, we first convert the mass of ampicillin sodium to moles:
1 g / 371 g/mol = 0.002695 moles of ampicillin sodium
Ampicillin sodium contains one sodium ion (Na+) per molecule. Therefore, the moles of sodium ions are equal to the moles of ampicillin sodium. To convert moles to milliequivalents (mEq), we use the fact that 1 mole of Na+ equals 1000 mEq:
0.002695 moles x 1000 mEq/mol = 2.695 mEq
Rounded to two decimal places, the sodium content is 2.70 mEq.
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Final answer:
Calculating the sodium content of a substance in milliequivalents (mEq) involves dividing the amount of the substance by its molecular weight, and then multiplying by the valency of sodium. In the case of 1g of ampicillin sodium with a molecular weight of 371, this calculation comes out to 2.7 mEq.
Explanation:
The sodium content in a substance, in milliequivalents (mEq), is determined by dividing the amount of the substance (in milligrams) by its molecular weight and then multiplying by the valency of sodium, which is 1. A gram of ampicillin sodium is the same as 1000 milligrams.
The molecular weight of ampicillin sodium is given as 371, so you do the calculation as follows: (1000/371) x 1. Using this formula, the answer is 2.7 mEq.
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