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Answer :
Answer:
The platform move before coming to rest again 0.045 m far
Explanation:
Given
Ball is in motion
M (Platform mass + 2 people mass)
V (recoil velocity of the platform)
m (ball mass)
v (velocity ball)
MV + mv = 0
Distance of the platform movement is
t (time that the ball is in the air)
x = Vt
t = [tex]\frac{L}{v - V}[/tex]
Knowing the platform and the ball are moving while the ball is in the air
x = [tex]\frac{V}{v - V} * L[/tex]
Also knowing that
[tex]\frac{V}{v} = \frac{-m}{M}[/tex]
This way,
x = [tex]((\frac{V}{v}) * L) / (1 - \frac{V}{v})[/tex] = [tex]-\frac{m*L}{M + m} = -\frac{3.63 kg * 2.50 m}{198 kg + 3.63 kg} = -0.045 m[/tex]
The minus sign means the displacement of the platform is in opposite direction to the displacement of the ball.
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