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A square slab is subjected to a factored load of 8 kPa. The

alpha coefficient = 250 and the factored moment is 17.5 kNm/m.

Selects the magnitude of the short free span.

Answer :

Answer

The magnitude of the short free span is approximately 0.00875 meters.

Given:

Factored load = 8 kPa

Alpha coefficient (α) = 250

Factored moment = 17.5 kNm/m

The short free span of a slab refers to the distance between supports where the moments and deflections are relatively small.

To find the short free span, we can use the formula:

Short free span (L) = (Factored moment / (Alpha coefficient * Factored load))

Substituting the given values:

L = (17.5 kNm/m) / (250 * 8 kPa)

First, we need to convert kNm to kN·m:

1 kNm = 1 kN·m

Next, we need to convert kPa to kN/m²:

1 kPa = 1 kN/m²

L = (17.5 kN·m/m) / (250 * 8 kN/m²)

L = 17.5 / (250 * 8)

L ≈ 0.00875 m

Therefore, the magnitude of the short free span is approximately 0.00875 meters.

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