High School

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Outside temperature over a day can be modeled as a sinusoidal function. Suppose the high temperature for the day is 100 degrees, and the low temperature of 70 degrees occurs at 5 AM. Assuming [tex]t[/tex] is the number of hours since midnight, find an equation for the temperature [tex]D[/tex] in terms of [tex]t[/tex]. Assume the next low is 24 hours later.

Answer :

Answer:

The function for the outside temperature is represented by [tex]T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right][/tex], where t is measured in hours.

Step-by-step explanation:

Since outside temperature can be modelled as a sinusoidal function, the period is of 24 hours and amplitude of temperature and average temperature are, respectively:

Amplitude

[tex]A = \frac{100\º-70\º}{2}[/tex]

[tex]A = 15\º[/tex]

Mean temperature

[tex]\bar T = \frac{70\º+100\º}{2}[/tex]

[tex]\bar T = 85\º[/tex]

Given that average temperature occurs six hours after the lowest temperature is registered. The temperature function is expressed as:

[tex]T(t) = \bar T + A \cdot \sin \left[2\pi\cdot\frac{t-6\,h}{\tau} \right][/tex]

Where:

[tex]\bar T[/tex] - Mean temperature, measured in degrees.

[tex]A[/tex] - Amplitude, measured in degrees.

[tex]\tau[/tex] - Daily period, measured in hours.

[tex]t[/tex] - Time, measured in hours. (where t = 0 corresponds with 5 AM).

If [tex]\bar T = 85\º[/tex], [tex]A = 15\º[/tex] and [tex]\tau = 24\,h[/tex], the resulting function for the outside temperature is:

[tex]T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right][/tex]

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