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Given a normal distribution with [tex]\mu = 50[/tex] and [tex]\sigma = 5[/tex], if you select a sample of [tex]n = 100[/tex], what is the probability that [tex]X[/tex] is:

a. Less than 47?

b. Between 47 and 49.5?

c. Above 51.1?

d. There is a 35% chance that [tex]X[/tex] is above what value?

Answer :

Final answer:

Using z-score, we can compute the probability that X is less than 47, between 47 and 49.5, above 51.1 and calculate the value that is above 35% chance.

Explanation:

To answer this question, we will use the concept of z-scores in statistics, which represents how many standard deviations away a given data point lies from the mean value.

a. less than 47: Here, Z = (47 - μ) / (σ / √n) = (47 - 50) / (5 / √100) = -0.6. So the required probability P(X < 47) = P(Z < -0.6) which can be obtained from z-table.

b. between 47 and 49.5:We need to compute the Z scores separately: Z1 = (47 - μ) / (σ / √n) = -0.6 and Z2 = (49.5 - μ) / (σ / √n) = -0.1. Therefore, P(47

c. above 51.1: Here, Z = (51.1 - μ) / (σ / √n) = 0.22. So the required probability P(X > 51.1) = P(Z > 0.22) = 1 - P(Z < 0.22) as we subtract from total area under curve which is 1.

d. There is a 35% chance that is above what value: Here we're looking for a Z score such that P(Z > z) = 0.35. Once the z score is found from z-table, we use the formula X = μ + Z * (σ / √n) to calculate the corresponding value of X.

Learn more about z-score here:

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