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Answer :
Final answer:
The magnitude of the centripetal force acting on the motorcycle as it passes over the top of the hill is approximately 16851 N, calculated using the formula for centripetal force: F = mv²/r.
Explanation:
In this scenario, we need to calculate the magnitude of the centripetal force acting on the motorcycle. Centripetal force refers to the force that keeps a body moving in a circular path. It's always directed towards the centre of the path, and its magnitude is given by F = mv²/r, where m is the mass of the object, v is the speed, and r is the radius of the path.Here, we have the mass (m) as 342 kg, the speed (v) as 25.0 m/s, and the radius (r) as 126 m. Plugging these values into the formula:
F = (342 kg)(25.0 m/s)² / 126 m
After calculations, we get:
F ≈ 16850.89 N
So, the magnitude of the centripetal force acting on the motorcycle is approximately 16851 N.
Learn more about Centripetal Force here:
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