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Answer :
The magnitude of the net gravitational force exerted by these objects on a 46. 0-kg object placed midway between them is 3.05 x [tex]10^{-8}[/tex] N.
To find force(F)
Given, mass of object1 (m1) = 115 kg
mass of object2 (m2) = 46 kg
distance between centers of masses (r) = 3.4 kg
Gravitational Force G = 6.6743 x [tex]10^{-11}[/tex] N[tex]\frac{m^{2} }{kg^{2} }[/tex]
As per Newton's law of universal gravitation:
"Every particle attracts every other particle in the universe with a force that is proportional to the product of their masses and inversely proportional to the square of the distance between their centers."
F = G [tex]\frac{m1m2}{r^{2} }[/tex]
= 6.6743 x [tex]10^{-11}[/tex] [tex]\frac{115 x 46}{3.4^{2} }[/tex]
= 6.6743 x [tex]10^{-11}[/tex] x [tex]\frac{5290}{11.56}[/tex]
= 6.6743 x [tex]10^{-11}[/tex] x 457.6125
= 3.05 x [tex]10^{-8}[/tex] N
Hence, Force F = 3.05 x [tex]10^{-8}[/tex] N.
To know more about Newton's law of universal gravitation: https://brainly.com/question/30667331
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