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The gravitational force between two volleyball players is [tex]3.9 \times 10^{-7} \, \text{N}[/tex]. If the masses of the players are 67 kg and 72 kg, what is their separation?

Answer :

Final answer:

The separation between the volleyball players is approximately 0.000067 meters.

Explanation:

The gravitational force between two objects can be calculated using the formula: F = G ( M1 * M2 ) / R^2

Where F is the gravitational force, G is the gravitational constant (6.674 × 10^-11 N·m²/kg²), M1 and M2 are the masses of the two objects, and R is their separation.

In this case, the masses of the two volleyball players are 67 kg and 72 kg, and the gravitational force is given as 3.9 x 10^-7 N. We can rearrange the formula to solve for R:

R = sqrt( G ( M1 * M2 ) / F )

Substituting the given values:

R = sqrt( (6.674 × 10^-11 N·m²/kg²) * ( 67 kg * 72 kg ) / (3.9 x 10^-7 N) )

R = sqrt( 4.56 * 10^-9 m² )

R ≈ 0.000067 m

Therefore, the separation between the volleyball players is approximately 0.000067 meters.

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