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A driver traveling at 60.0 mph tries to stop the car and finds that the brakes have failed. The emergency brake is then pulled, and the car comes to a stop in 456 ft.

Find the car's deceleration.

Answer :

Final answer:

The car's deceleration is calculated using the kinematic equation and converting all units consistently. It is found to be -8.5 feet/second².

Explanation:

To solve this problem, you will need to understand the basic concepts of kinematics and make use of the equation: v^2 = u² + 2as, where 'v' is the final velocity, 'u' is the initial velocity, 'a' is the acceleration (in this case deceleration), and 's' is the distance.

In this situation, the driver is initially traveling at 60 mph which we need to convert into feet per second (fps) because the stopping distance is given in feet. We know that 1 mph is approximately 1.467 fps. Thus, 60 mph is equal to 88 fps (60 x 1.467).

Then, since the car comes to a stop, the final velocity 'v' is 0. We can now substitute these values into the formula.

So, we have 0 = (88)² + 2*a*456. Solving this formula for 'a', the car's deceleration comes up to be approximately -8.5 feet/sec2.

Learn more about deceleration here:

https://brainly.com/question/13802847

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