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In the figure, O is the center of the circle SQR. Given that ∠RSQ = 110° and PSR is a straight line, calculate ∠QPS.

Option 1: QPS = 35°
Option 2: QPS = 40°
Option 3: QPS = 45°
Option 4: QPS = 50°

Answer :

Final answer:

The measure of angle QPS is 70°. None of the above option.

Explanation:

To find the measure of angle QPS, we can use the property that the angles formed by a chord subtended at the circumference of a circle are equal. In this case, RSQ is equal to RQS because they both subtend the same arc. Since RSQ = 110°, this means that RQS = 110° as well. Because RSQ is a straight line, therefore ∠QRS + ∠QRO = 180°.

But it is known that RSQ = 110° which is an angle at the center. Hence, ∠QRS = 180° − 110° = 70°. In a cyclic quadrilateral, the sum of opposite angles is 180°. Therefore, ∠QPS + ∠QRO = 180°. As ∠QRO = 110°, then ∠QPS = 180° − 110° = 70°. Since RQS and QPS form a straight line, their sum is 180°. So, QPS = 180° - RQS = 180° - 110° = 70°. None of the above option.

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