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Given:
- [tex]E_{Na} = 50 \, \text{mV}[/tex]
- [tex]E_{K} = -90 \, \text{mV}[/tex]
- [tex]E_{Cl} = -55 \, \text{mV}[/tex]

If neuron X has a [tex]G_{Na}[/tex] that is 100 times as large as either [tex]G_{K}[/tex] or [tex]G_{Cl}[/tex], what would be the approximate value of the resting membrane potential ([tex]V_{m}[/tex])?

A. -50 mV
B. -70 mV
C. -10 mV
D. +50 mV

Answer :

Final answer:

Given the stated parameters, the approximate value of the resting membrane potential for neuron X would be closer to the sodium equilibrium potential or +50mV.

Explanation:

The resting membrane potential of a neuron, or cell, is influenced by the concentrations of ions, namely sodium (Na), potassium (K), and chlorine (Cl), and their respective permeabilities, denoted by GNa, GK, and GCl. Given ENa = 50mV, EK = -90mV, and ECl = -55mV, if a neuron X had a GNa that was 100 times as large as either GK or GCl, the cell would be mostly permeable to Na ions. This means that the resting membrane potential (Vm) would primarily reflect the equilibrium potential of Na, which is +50mV.

However, it's important to understand that in real neurons, the situation is more complex. The resting membrane potential is commonly around -70mV. This is due to the activity of the sodium-potassium pump and leakage channels that allow the slow movement of Na and K ions across the cell membrane, contributing to maintaining this membrane potential.

Learn more about Resting Membrane Potential here:

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