High School

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Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a [tex]$\square$[/tex] chance that the offspring will be heterozygous.

[tex]\[

\begin{array}{|c|c|c|}

\hline

& W & w \\

\hline

W & Ww & ww \\

\hline

w & Ww & ww \\

\hline

\end{array}

\][/tex]

2. If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is [tex]$\square$[/tex].

[tex]\[

\begin{array}{|c|c|c|}

\hline

& W & w \\

\hline

W & WW & Ww \\

\hline

W & WW & Ww \\

\hline

\end{array}

\][/tex]

Answer :

Sure! Let's solve the problem step-by-step.

### Problem 1:
We're crossing a heterozygous male (Ww) with a homozygous recessive female (ww).

- Parents' Genotypes:
- Male: Ww
- Female: ww

To find the possible genotypes of the offspring, we can use a Punnett square. Here, we'll pair each allele from the male with each allele from the female:

```
| W | w
---------------
w | Ww | ww
---------------
w | Ww | ww
---------------
```

Possible Offspring Genotypes:
- 2 offspring with Ww
- 2 offspring with ww

This gives us a total of 4 possible combinations. Out of these, 2 are heterozygous (Ww).

- Probability of Heterozygous Offspring (Ww):
[tex]\[
\frac{\text{Number of Ww}}{\text{Total Offspring}} = \frac{2}{4} = 0.5
\][/tex]

So, there is a 0.5 chance that the offspring will be heterozygous.

### Problem 2:
Now, we cross a heterozygous (Ww) with a homozygous dominant (WW).

- Parents' Genotypes:
- One Parent: Ww
- Other Parent: WW

Again, we use a Punnett square:

```
| W | W
---------------
W | WW | WW
---------------
w | Ww | Ww
---------------
```

Possible Offspring Genotypes:
- 2 offspring with WW
- 2 offspring with Ww

Here, all the offspring will be either WW or Ww. None will be homozygous recessive (ww).

- Probability of Homozygous Recessive Offspring (ww):
[tex]\[
\frac{\text{Number of ww}}{\text{Total Offspring}} = \frac{0}{4} = 0.0
\][/tex]

Thus, there is a 0.0 chance of having homozygous recessive offspring.

I hope this helps you understand how to determine the probabilities of different genotypes using Punnett squares! If you have any further questions, feel free to ask.

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