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Answer :
Final answer:
Using the equation of motion, you can determine that it will take approximately 1.22 seconds for a feather to fall to the moon's surface from a height of 2 meters given the acceleration due to gravity on the moon (1.69m/s²). This calculation assumes a vacuum condition with no air resistance.
Explanation:
The question is asking about the time it would take for a feather to fall to the moon's surface from a height of 2m given the acceleration due to gravity on the moon. In physics, we can use the equation of motion to solve this problem. The equation that relates distance (d), acceleration (a), and time (t) is d=1/2at². The distance in this case is 2m and the acceleration is 1.69m/s². Knowing this, we can rearrange the equation to solve for time:
t = √(2d/a) = √(2*2m/1.69m/s²) ≈ 1.22 seconds.
So, it will take approximately 1.22 seconds for the feather to fall to the moon's surface from a height of 2 meters assuming a vacuum condition with no air resistance. It's important to note that this is a theoretical situation and it assumes the feather and the moon are the only two objects in this system (i.e., we are not considering the Earth's gravitational pull on the feather).
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