We appreciate your visit to A 30 0 kg child sits on one end of a long uniform beam with a mass of 20 0 kg and a 40 0. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
let the length of the beam be "L"
from the diagram
AD = length of beam = L
AC = CD = AD/2 = L/2
BC = AC - AB = (L/2) - 1.10
BD = AD - AB = L - 1.10
m = mass of beam = 20 kg
m₁ = mass of child on left end = 30 kg
m₂ = mass of child on right end = 40 kg
using equilibrium of torque about B
(m₁ g) (AB) = (mg) (BC) + (m₂ g) (BD)
30 (1.10) = (20) ((L/2) - 1.10) + (40) (L - 1.10)
L = 1.98 m
Thanks for taking the time to read A 30 0 kg child sits on one end of a long uniform beam with a mass of 20 0 kg and a 40 0. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
The total length of the beam is determined as 1.98 m.
Principle of moment
The length of the beam is determined by applying the principle of moment as shown below;
Take moment about the pivot;
Let the total length of the beam = x
mid point of the beam = 0.5 x
(30 x 1.1) = 20(0.5x - 1.1) + 40(x - 1.1)
33 = 10x - 22 + 40x - 44
99 = 50x
x = 99/50
x = 1.98 m
Thus, the total length of the beam is determined as 1.98 m.
Learn more about principle of moment here: https://brainly.com/question/26117248
