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Answer :
Final answer:
The solar panel wastes 600J of energy as heat every second, and its efficiency is 20%.
Explanation:
The energy 'wasted' in the form of heat by the solar panel every second can be calculated by subtracting the amount of energy converted into electrical energy from the total energy absorbed. In this case, the solar panel absorbs 750J of light energy every second and converts 150J of that into electrical energy, so the wasted energy is:
Energy wasted = Energy absorbed - Energy converted into electricity
Energy wasted = 750J - 150J = 600J
The efficiency of the solar panel can be calculated by taking the ratio of the electrical energy output to the energy input (absorbed) and converting it to a percentage:
Efficiency = (Energy converted into electricity / Energy absorbed) × 100%
Efficiency = (150J / 750J) × 100% = 20%
So, the efficiency of this solar panel is 20%.
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