We appreciate your visit to The temperature of a 12 58 g sample of calcium carbonate increases from 23 6 C to 38 2 C If the specific heat of. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Answer:
150.6 Joules
Explanation:
Calorimetry problem must be solved by the calorimetry formula.
Q = c . m . ΔT
ΔT = Final T° - Initial T°
c = specific heat (Notice, that in the unit we have K as unit for T°, and the T° is in °C. We don't need to make the conversion, because is a Δ)
For example 100°C - 50°C = 50°C
373K - 323K = 50 K
So let's replace data given: Q = 0.82 J/g.K . 12.58 g . (38.2 - 23.6)
Q = 150.6 Joules
We assume no heat lost by sourrounding
Thanks for taking the time to read The temperature of a 12 58 g sample of calcium carbonate increases from 23 6 C to 38 2 C If the specific heat of. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
