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Answer :
Final answer:
The number of natural numbers less than 7,000 that can be formed using the given digits is 6250.The correct option is b) 6250.
Explanation:
To find the number of natural numbers less than 7,000 that can be formed using the digits 0, 1, 3, 7, and 9 with repetition allowed, we can consider numbers by the number of digits they have, from one to four.
For a one-digit number, there are 5 possibilities (0, 1, 3, 7, 9).For a two-digit number, there are 5 possibilities for the first digit and 5 for the second digit, making 5 x 5 = 25 possibilities.For a three-digit number, the possibilities are 5 x 5 x 5 = 125.
To find the number of natural numbers less than 7,000 that can be formed by using the digits 0, 1, 3, 7, 9 (repetition of digits allowed), we calculate it as follows:
- For each place value (units, tens, hundreds, etc.), there are 5 choices (0, 1, 3, 7, 9).
- Since we are looking for numbers less than 7,000, the highest place value (thousands) cannot be 0, so it has 4 choices (1, 3, 7, 9).
- Multiplying the choices for each place value gives us: 5 x 5 x 5 x 4 = 6250.
The correct option is b) 6250.
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