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Answer :
Final answer:
The z-score corresponding to a sample mean of 130 lbs. with a sample size of 35, when the the population mean is 143 lbs. and the standard deviation is 29 lbs., is approximately -1.65
Explanation:
To calculate the z-score corresponding to the sample mean, we use the formula for the z-score, which is (X - μ) / (σ / √n), where X is the sample mean, μ is the population mean, σ is the standard deviation, and n is the sample size.
Substituting the values from the question into the formula, we find the z-score is (130 - 143) / (29 / √35) = -13 / (29 / √35) which gives us a z-score of roughly -1.65 (4th option), assuming that the population mean and standard deviation were 143 lbs. and 29 lbs. respectively, not the negative values.
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