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Answer :
To find the zeros of the function [tex]\( g(c) = 25c^2 + 95c \)[/tex], we need to determine the values of [tex]\( c \)[/tex] that make the expression equal to zero.
1. Set the function equal to zero:
[tex]\[
25c^2 + 95c = 0
\][/tex]
2. Factor out the common term:
Both terms on the left side have a common factor of [tex]\( c \)[/tex]. We can factor this out:
[tex]\[
c(25c + 95) = 0
\][/tex]
3. Set each factor equal to zero:
For the product to be zero, at least one of the factors must be zero.
[tex]\[
c = 0 \quad \text{or} \quad 25c + 95 = 0
\][/tex]
4. Solve each equation:
- The first equation [tex]\( c = 0 \)[/tex] is already solved.
- For the second equation, solve for [tex]\( c \)[/tex]:
[tex]\[
25c + 95 = 0
\][/tex]
Subtract 95 from both sides:
[tex]\[
25c = -95
\][/tex]
Divide both sides by 25:
[tex]\[
c = \frac{-95}{25}
\][/tex]
Simplify the fraction:
[tex]\[
c = -3.8
\][/tex]
Thus, the zeros of the function [tex]\( g(c) = 25c^2 + 95c \)[/tex] are:
[tex]\[
c = 0 \quad \text{and} \quad c = -3.8
\][/tex]
Among the given options, the correct one is:
[tex]\[ c = 0, \frac{19}{5} \][/tex]
However, the correct zeros based on the solution are:
\[ c = 0, -3.8]
It seems there might be a mismatch in the given options and what we calculated. The correct zeros should be [tex]\( c = 0 \)[/tex] and [tex]\( c = -3.8 \)[/tex]
1. Set the function equal to zero:
[tex]\[
25c^2 + 95c = 0
\][/tex]
2. Factor out the common term:
Both terms on the left side have a common factor of [tex]\( c \)[/tex]. We can factor this out:
[tex]\[
c(25c + 95) = 0
\][/tex]
3. Set each factor equal to zero:
For the product to be zero, at least one of the factors must be zero.
[tex]\[
c = 0 \quad \text{or} \quad 25c + 95 = 0
\][/tex]
4. Solve each equation:
- The first equation [tex]\( c = 0 \)[/tex] is already solved.
- For the second equation, solve for [tex]\( c \)[/tex]:
[tex]\[
25c + 95 = 0
\][/tex]
Subtract 95 from both sides:
[tex]\[
25c = -95
\][/tex]
Divide both sides by 25:
[tex]\[
c = \frac{-95}{25}
\][/tex]
Simplify the fraction:
[tex]\[
c = -3.8
\][/tex]
Thus, the zeros of the function [tex]\( g(c) = 25c^2 + 95c \)[/tex] are:
[tex]\[
c = 0 \quad \text{and} \quad c = -3.8
\][/tex]
Among the given options, the correct one is:
[tex]\[ c = 0, \frac{19}{5} \][/tex]
However, the correct zeros based on the solution are:
\[ c = 0, -3.8]
It seems there might be a mismatch in the given options and what we calculated. The correct zeros should be [tex]\( c = 0 \)[/tex] and [tex]\( c = -3.8 \)[/tex]
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