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Two cars leave towns 950 kilometers apart at the same time and travel toward each other. One car's rate is 14 kilometers per hour less than the other's. If they meet in 5 hours, what is the rate of the slower car?

Answer :

Final answer:

Both the faster and the slower car cover the total distance of 950 kilometers in 5 hours jointly. Their combined speed is 190 km/hour. The slower car is traveling 14 km/hour less than the faster car, which results in the slower car's speed being 88 km/hour.

Explanation:

This question requires solving a relative speed problem. The total distance covered by both cars is 950 kilometers in 5 hours, which means they were effectively moving towards each other at a combined speed of 950 / 5 = 190 kilometers per hour. Let's use a variable to denote the speed of the faster car, label it R (km/hour). Consequently, the slower car would be moving at a speed of R - 14 km/hour.

Since the cars are moving towards each other, their speeds are additive, thus R + (R - 14) = 190. Solving this equation for R, we find that the speed of the faster car is 102 km/hour, and as a result, the speed of the slower car is 102 - 14 = 88 km/hour.

Learn more about Relative Speed here:

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