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Determine the number of atoms of O in the following compounds:

1. 38.1 moles of \(\text{Al}_2(\text{CO}_3)_3\).
2. 86.0 moles of \(\text{Al}_2(\text{SO}_4)_3\).
3. 88.6 moles of \(\text{Fe}(\text{ClO}_2)_3\).

Answer :

To calculate the number of atoms of oxygen in 86.0 moles of Al2(SO4)3, we follow the same steps as before:
86.0 moles x 6.022 x 10^23 molecules/mole = 5.181 x 10^25 molecules of Al2(SO4)3
5.181 x 10^25 molecules x 12 atoms/molecule = 6.217 x 10^26 atoms of oxygen.

Let's start with Al2(CO3)3. In this compound, there are three carbonate (CO3) groups, and each carbonate group contains one atom of oxygen. So, in one molecule of Al2(CO3)3, we have a total of 3 atoms of oxygen.

To calculate the number of atoms of oxygen in 38.1 moles of Al2(CO3)3, we can use Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole.

First, we calculate the number of molecules of Al2(CO3)3 in 38.1 moles by multiplying the number of moles by Avogadro's number:
38.1 moles x 6.022 x 10^23 molecules/mole = 2.297 x 10^25 molecules of Al2(CO3)3

Since each molecule of Al2(CO3)3 has 3 atoms of oxygen, we multiply the number of molecules by 3 to get the total number of atoms of oxygen:
2.297 x 10^25 molecules x 3 atoms/molecule = 6.892 x 10^25 atoms of oxygen.

Next, let's consider Al2(SO4)3. In this compound, there are three sulfate (SO4) groups, and each sulfate group contains four atoms of oxygen. So, in one molecule of Al2(SO4)3, we have a total of 3 x 4 = 12 atoms of oxygen.
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Rewritten by : Barada

The number of atoms of O in 38.1 moles of Al₂(CO₃)₃ 2.06 × 10²⁶ oxygen atoms. 86 moles ofAl₂(SO₄)₃ contains 6.21 × 10²⁶ oxygen atoms. 88.6 moles of Fe(ClO₂)₃ contains 3.20 oxygen atoms.

1.The given formula of the compound = Al₂(CO₃)₃

From the chemical formula it can be easily said that 1 mole of Al₂(CO₃)₃ contains-

(i) 2 mole of Aluminum atom

(ii) 3 mole of Carbon atom

(iii) 9 mole of Oxygen atom

Thus, 38.1 moles of Al₂(CO₃)₃ contains ( 38.1 times 9) mole = 342.9 mole of Oxygen atom.

Now, we know that 1 mole of oxygen atom contains 6.022 × 10²³ oxygen atom

342.9 mole of oxygen atom contains (342.9 \times 6.022 \times 1023 ) = 2.06 \times 1026 oxygen atom

Hence, the answer is 2.06 × 10²⁶ oxygen atom

2.The given formula of the compound = Al₂(SO₄)₃

From the chemical formula it can be easily said that 1 mole ofAl₂(SO₄)₃contains-

(i) 2 mole of Aluminum atom

(ii) 3 mole of Sulfur atom

(iii) 12 mole of Oxygen atom

Thus, 86 moles ofAl₂(SO₄)₃ contains ( 86 \times 12) mole = 1032 mole of Oxygen atom.

Now, we know that 1 mole of oxygen atom contains 6.022 × 10²³ oxygen atom

1032 mole of oxygen atom contains (1032 \times 6.022 \times 1023 ) = 6.21 \times 1026 oxygen atom

Hence, the answer is 6.21×10²⁶ oxygen atom

3.The given formula of the compound = Fe(ClO₂)₃

From the chemical formula it can be easily said that 1 mole of Fe(ClO₂)₃contains-

(i) 1 mole of iron atom

(ii) 3 mole of chlorine atom

(iii) 6 mole of Oxygen atom

Thus, 88.6 moles of Fe(ClO₂)₃contains ( 88.6 \times 6) mole = 531.6 mole of Oxygen atom.

Now, we know that 1 mole of oxygen atom contains 6.022 × 10²³ oxygen atom

531.6 mole of oxygen atom contains (531.6 \times 6.022 \times 1023 ) = 3.20 \times 1026 oxygen atom

Hence, the answer is 3.20 × 10²⁶ oxygen atom

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