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A black mamba snake has a length of 3.50 m and a top speed of 4.90 m/s. Suppose a mongoose and a black mamba find themselves nose to nose. In an effort to escape, the snake accelerates past the mongoose at 7.37 m/s² from rest. How much time [tex]t_{\text{top}}[/tex] does it take the snake to reach its top speed?

Answer :

Final answer:

Using the formula for acceleration, it can be calculated that the Black Mamba snake will take around 0.665 seconds to reach its top speed of 4.9 m/s when escaping from the mongoose.

Explanation:

The problem posed is a classic instance of the physics concept—acceleration. Based on the information given—initial velocity (0 m/s), final velocity (4.9 m/s), and the acceleration (7.37 m/s²)—we can use the formula b, where v is the final velocity, u is the initial velocity, a is acceleration, and t is time.

In this case, as the Black Mamba snake is accelerating from rest, we can say that its initial velocity is 0. Reordering the equation to solve for time, we get t = (v - u) / a.

Substituting in our given values, we get t = (4.9m/s - 0m/s) / 7.37m/s². That yields a result of approximately 0.665 seconds. This is the amount of time it takes for the Black Mamba snake to reach its top speed of 4.9 m/s when escaping the mongoose.

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