High School

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If [tex]$f(4)=246.4$[/tex] when [tex]$r=0.04$[/tex] for the function [tex]$f(t)=P e^{rt}$[/tex], then what is the approximate value of [tex]$P$[/tex]?

A. 289
B. 50
C. 1220
D. 210

Answer :

To find the approximate value of [tex]\( P \)[/tex] for the function [tex]\( f(t) = P e^{rt} \)[/tex], we can use the given information [tex]\( f(4) = 246.4 \)[/tex] when [tex]\( r = 0.04 \)[/tex]. Let's go through the steps to solve for [tex]\( P \)[/tex].

1. Write down the function with the given values:
[tex]\[
f(4) = P \times e^{r \cdot t}
\][/tex]
Plugging in the values we have:
[tex]\[
246.4 = P \times e^{0.04 \times 4}
\][/tex]

2. Simplify the exponent:
[tex]\[
0.04 \times 4 = 0.16
\][/tex]
So the equation becomes:
[tex]\[
246.4 = P \times e^{0.16}
\][/tex]

3. Calculate [tex]\( e^{0.16} \)[/tex]. This is approximately equal to 1.17351.

4. Solve for [tex]\( P \)[/tex] by dividing both sides by [tex]\( e^{0.16} \)[/tex]:
[tex]\[
P = \frac{246.4}{1.17351}
\][/tex]

5. When you do the division:
[tex]\[
P \approx 209.97
\][/tex]

Thus, the approximate value of [tex]\( P \)[/tex] is closest to 210. Therefore, the correct answer is:

D. 210

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