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Answer :
Answer:
0.484 g
Step-by-step explanation:
N/No = (1/2)^t/t1/2
No = mass of cesium-137 originally present
N= mass of cesium-137 at time t
t1/2= half life of cesium-137
t = time taken
N/5.5=(1/2)^105/30
N/5.5=(1/2)^3.5
N/5.5= 0.088
N = 5.5 * 0.088
N= 0.484 g
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