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Ammonia (\( \text{NH}_3 \), MM 17.031 g/mol) and hypobromite (\( \text{OBr}^- \)) react according to the following chemical reaction:

\[ 2 \text{NH}_3 + 3 \text{OBr}^- \rightarrow \text{N}_2 + 3 \text{Br}^- + 3 \text{H}_2\text{O} \]

Suppose 0.731 g of ammonia reacts with 35.9 mL of a hypobromite solution. Calculate the concentration of the hypobromite solution.

Concentration:

Answer :

Final answer:

To calculate the concentration of the hypobromite solution, use stoichiometry and the given information. Convert the mass of ammonia to moles, then use the balanced chemical equation to find the moles of hypobromite solution that reacted. Finally, calculate the concentration by dividing the moles of hypobromite solution by the volume in liters.

Explanation:

To calculate the concentration of the hypobromite solution, we need to use stoichiometry and the given information. We know that 0.731 g of ammonia reacts with 35.9 mL of the hypobromite solution. First, we need to convert the mass of ammonia to moles using its molar mass. Then, we can use the balanced chemical equation to find the moles of hypobromite solution that reacted. Finally, we can calculate the concentration by dividing the moles of hypobromite solution by the volume in liters.



Let's go step by step:



  1. Convert the mass of ammonia to moles. Given that the molar mass of ammonia (NH3) is 17.031 g/mol, we can use the formula moles = mass / molar mass. In this case, moles of ammonia = 0.731 g / 17.031 g/mol = 0.0429 mol.
  2. From the balanced chemical equation, we can see that 2 moles of ammonia react with 3 moles of hypobromite solution. So, the moles of hypobromite solution = (0.0429 mol ammonia) * (3 mol hypobromite solution / 2 mol ammonia) = 0.0644 mol hypobromite solution.
  3. Finally, to calculate the concentration of the hypobromite solution, we divide the moles of hypobromite solution by the volume in liters. Since 35.9 mL is given, we convert it to liters by dividing by 1000 (1 L = 1000 mL). Concentration = (0.0644 mol hypobromite solution) / (35.9 mL / 1000 mL/L) = 0.00179 M hypobromite solution.

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