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The angle of elevation from the top of one building to the top of another is [tex]26^{\circ}[/tex]. If the shorter building is 400 feet tall and the buildings are 1500 feet apart, how tall is the other building?

Answer :

To solve this problem, we need to find the height of the taller building using the angle of elevation and the distance between the buildings.

Let's break it down step-by-step:

1. Understand the Problem:
- We have two buildings. The shorter one is 400 feet tall.
- The distance between the buildings is 1500 feet.
- The angle of elevation from the top of the shorter building to the top of the taller building is [tex]\(26^\circ\)[/tex].

2. Set Up the Trigonometric Ratio:
- The tangent of an angle in a right triangle is the ratio of the opposite side to the adjacent side.
- In this problem, the opposite side is the height difference between the two buildings, and the adjacent side is the distance between them (1500 feet).
- Mathematically, this is expressed as:
[tex]\[
\tan(26^\circ) = \frac{\text{height difference}}{1500}
\][/tex]

3. Calculate the Height Difference:
- Rearrange the formula to solve for the height difference:
[tex]\[
\text{height difference} = \tan(26^\circ) \times 1500
\][/tex]

4. Find the Height of the Taller Building:
- Once we have the height difference, we can find the height of the taller building by adding the height difference to the height of the shorter building:
[tex]\[
\text{height of the taller building} = 400 + \text{height difference}
\][/tex]

5. Result:
- The calculated height difference is approximately 731.6 feet.
- Therefore, the height of the taller building is approximately 1131.6 feet.

That's how you determine the height of the taller building given the angle of elevation and the distance between the two buildings.

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Rewritten by : Barada