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Answer :
Let [tex]$p$[/tex] represent the total number of pages in the novel. According to the problem, John read 114 pages, and this number is 3 pages less than one third of the novel. This relationship can be written as:
[tex]$$114 = \frac{1}{3}p - 3.$$[/tex]
Step 1: Write the equation.
John's pages read equals one third of the whole novel minus 3, therefore:
[tex]$$114 = \frac{1}{3}p - 3.$$[/tex]
Step 2: Isolate the fraction.
Add 3 to both sides of the equation:
[tex]$$114 + 3 = \frac{1}{3}p,$$[/tex]
[tex]$$117 = \frac{1}{3}p.$$[/tex]
Step 3: Solve for [tex]$p$[/tex].
Multiply both sides by 3:
[tex]$$p = 117 \times 3,$$[/tex]
[tex]$$p = 351.$$[/tex]
Thus, the equation that best describes the situation is:
[tex]$$114 = \frac{1}{3}p - 3,$$[/tex]
and the total number of pages in the novel is [tex]$351$[/tex].
[tex]$$114 = \frac{1}{3}p - 3.$$[/tex]
Step 1: Write the equation.
John's pages read equals one third of the whole novel minus 3, therefore:
[tex]$$114 = \frac{1}{3}p - 3.$$[/tex]
Step 2: Isolate the fraction.
Add 3 to both sides of the equation:
[tex]$$114 + 3 = \frac{1}{3}p,$$[/tex]
[tex]$$117 = \frac{1}{3}p.$$[/tex]
Step 3: Solve for [tex]$p$[/tex].
Multiply both sides by 3:
[tex]$$p = 117 \times 3,$$[/tex]
[tex]$$p = 351.$$[/tex]
Thus, the equation that best describes the situation is:
[tex]$$114 = \frac{1}{3}p - 3,$$[/tex]
and the total number of pages in the novel is [tex]$351$[/tex].
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