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Answer :
The mass (in grams) of water, H₂O that would theoretically be produced is 25.70 g
How do I determine the mass of water that would be p roduced?
We'll begin by writing the balanced equation for the reaction of NH₄Cl to produce water. This given below:
NH₄Cl + NaOH -> NH₃ + NaCl + H₂O
- Molar mass of NH₄Cl = 53.5 g/mol
- Mass of NH₄Cl from the balanced equation = 1 × 53.5 = 53.5 g
- Molar mass of H₂O = 18 g/mol
- Mass of H₂O from the balanced equation = 1 × 18 = 18 g
From the balanced equation above,
53.5 g of NH₄Cl reacted to produce 18 g H₂O
Now, we shall determine the mass of water, H₂O produced from the reaction of 76.4 g of NH₄Cl. Details below:
From the balanced equation above,
53.5 g of NH₄Cl reacted to produce 18 g H₂O
Therefore,
76.4 g of NH₄Cl will react to produce = (76.4 × 18) / 53.5 = 25.70 g of H₂O
Thus, the mass of water, H₂O produced is 25.70 g
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