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Answer :
Answer is: the molarity of this glucose solution is 0.278 M.
m(C₆H₁₂O₆) = 5.10 g.
n(C₆H₁₂O₆) = m(C₆H₁₂O₆) ÷ M(C₆H₁₂O₆) .
n(C₆H₁₂O₆) = 5.10 g ÷ 180.156 g/mol.
n(C₆H₁₂O₆) = 0.028 mol.
V(solution) = 100.5 mL ÷ 1000 mL/L.
V(solution) = 0.1005 L.
c(C₆H₁₂O₆) = n(C₆H₁₂O₆) ÷ V(solution).
c(C₆H₁₂O₆) = 0.028 mol ÷ 0.1005 L.
c(C₆H₁₂O₆) = 0.278 mol/L.
m(C₆H₁₂O₆) = 5.10 g.
n(C₆H₁₂O₆) = m(C₆H₁₂O₆) ÷ M(C₆H₁₂O₆) .
n(C₆H₁₂O₆) = 5.10 g ÷ 180.156 g/mol.
n(C₆H₁₂O₆) = 0.028 mol.
V(solution) = 100.5 mL ÷ 1000 mL/L.
V(solution) = 0.1005 L.
c(C₆H₁₂O₆) = n(C₆H₁₂O₆) ÷ V(solution).
c(C₆H₁₂O₆) = 0.028 mol ÷ 0.1005 L.
c(C₆H₁₂O₆) = 0.278 mol/L.
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Rewritten by : Barada
The molarity of the solution is approximately A. 0.282 M.
The molarity of the glucose solution is calculated by first determining the moles of glucose and then dividing by the volume in liters.
- To determine the molarity of a glucose solution, we need to follow these steps:
Calculate the number of moles of glucose:
- First, use the molar mass of glucose (C₆H₁₂O₆), which is approximately 180.16 g/mol:
- Number of moles of glucose = mass of glucose (g) / molar mass of glucose (g/mol)
- Number of moles of glucose = 5.10 g / 180.16 g/mol ≈ 0.0283 moles
Convert the solution volume from milliliters to liters:
- Volume in liters = 100.5 mL * (1 L / 1000 mL) ≈ 0.1005 L
Calculate the molarity:
- Molarity (M) = number of moles of solute / volume of solution in liters
- Molarity (M) = 0.0283 moles / 0.1005 L ≈ 0.2819 M
- Thus, the molarity of the glucose solution is approximately 0.282 M.
Correct question is: A 100.5 ml intraveneous (iv) solution contains 5.10 g glucose (C₆H₁₂O₆) . What is the molarity of this solution?
A .0.282M
B. 1.234M
C. 3.245M
D. 0.234M
