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Suppose you have a 112-kg wooden crate resting on a wood floor with a coefficient of static friction [s = 0.5].

(a) What maximum force can you exert horizontally on the crate without moving it?

Answer :

Final answer:

The maximum force that can be exerted horizontally on the crate without moving it, also known as the force of static friction, is 548.8 N.

Explanation:

This is a problem that involves the concept of static friction, which is what keeps the crate from moving. The force of static friction (Fs) is equal to the coefficient of static friction (s) times the normal force (FN), which is the weight of the crate.

Given that the weight of the crate is its mass (m) times gravitational acceleration (g=9.8 m/s²), we can find FN to be 112 kg * 9.8 m/s² = 1097.6 N. Therefore, the maximum force to keep the crate from moving is Fs = s*FN = 0.5*1097.6 N = 548.8 N.

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Rewritten by : Barada

Final answer:

The maximum force that can be exerted on the wooden crate without moving it is 329.28 N.

Explanation:

To determine the maximum force that can be exerted horizontally on the wooden crate without moving it, we need to consider the concept of static friction.

In this case, the maximum force is equal to the product of the coefficient of static friction (0.3) and the normal force.

The normal force, denoted as N, is equal to the weight of the crate, which in this case is 112 kg multiplied by the acceleration due to gravity, which is approximately 9.8 m/s^2.

Therefore, N = 112 kg x 9.8 m/s^2 = 1097.6 N.

Using the formula for maximum force, F_max = coefficient of static friction x normal force, we calculate F_max = 0.3 x 1097.6 N = 329.28 N.

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