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Answer :
Final answer:
The horizontal velocity of the ball as it left the table is 3.76 m/s.
Explanation:
To find the horizontal velocity of the ball as it left the table, we need to use the equations of motion for a projectile. First, we can determine the time it takes for the ball to hit the ground by using the equation for the vertical distance traveled:
h = 0.5 * g * t^2
Where h is the total vertical distance (99.4 cm), g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken. Rearranging the equation gives:
t^2 = 2 * h / g
t = sqrt(2 * h / g)
Plugging in the values gives t = sqrt(2 * 0.994 / 9.8) = 0.45 s. Now, we can use the equation for the horizontal distance traveled:
d = v * t
Where d is the horizontal distance, v is the horizontal velocity, and t is the time taken. Rearranging the equation gives:
v = d / t
Plugging in the values gives v = 1.69 m / 0.45 s = 3.76 m/s.
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