Answer :

In parallelogram QPQR diagonals QO and PR intersect at S. The statement is c,

What is parallelogram?

A parallelogram is a simple quadrilateral with two pairs of parallel sides.

We can have more arguments to prove that PQRS is a rhombus, but, the argument that we will use here is:

Let's look at the first statement, we have

PT> QT

That's not correct, it would just prove that QR/2 > PS/2,

PR = QS

This statement implies

PR² = QS²

PS² + SR² = PQ² +QR²

We cannot conclude that

PS + SR = PQ =QR

The next statement is

PT = QT

A rhombus can have different diagonals, and in fact, they have. Then let's go to the next one

ST = QT

It also does not exactly say it's a rhombus, it's a parallelogram property.

By doing that we have that the diagonal bisects the angle

That implies that angle b is also bisected.

The last statement is

That's the vertex angle, it's true always, not only in that case, therefore the only possible answer is

Therefore, the correct option is C,

Learn more about parallelograms, here:

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The question is incomplete. The options are added in the picture.

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