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Answer :
Final answer:
To find the energy stored in a capacitor, use the formula Energy = 0.5 x Capacitance x Voltage^2. Applying this to the given scenario, the energy stored in the 150 µF capacitor is 33.6 µJ, corresponding to option c. Therefore the correct answer is c.
Explanation:
The energy stored in a capacitor is electrical potential energy, which is stored in the electric field between the plates of the capacitor when it is charged. Capacitors are electronic components used in circuits to store and release electrical energy.
Energy stored in a capacitor can be calculated using the formula:
Energy (J) = 0.5 x Capacitance (F) x Voltage2 (V)
Given that the capacitor stores 10 J of energy with a capacitance of 100 µF, the voltage across the capacitor can be calculated as 100 V. Therefore, the energy stored in a 150 µF capacitor when 150 V is applied would be 33.6 µJ.
This formula shows that the energy stored in a capacitor is proportional to the square of the voltage across the capacitor and directly proportional to the capacitance. It also implies that the energy stored increases quadratically with the voltage.
The energy stored in a capacitor represents the work done to charge the capacitor and establish an electric field between its plates. This energy can be released when the capacitor discharges, providing electrical power to a circuit or device.
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